The PHP Basics

<?php

//this i a single line comment

/*

this is a
multi line
comment
*/

$foo = 1; // this is a pre-defined variable
$bar = "-1"; //so is this

$foobar = $foo + $bar; // this is a simple addition statement

echo $foobar; //this returned the answer to the users browser. everything is not seen except the answer.



?>

Do you find anything wrong with this part of my code?

Code:

<p align="center">
Date: <?php echo $todayis ?>


Thank You : <?php echo $visitor ?> ( <?php echo $visitormail ?> )



Attention: <?php echo $attn ?>

 
Message:
 
<?php $notesout = str_replace("\r", "<br/>", $notes);
echo $notesout; ?>


<?php echo $ip ?>
</p>

well, since your using un-defined variables, the code would be invaild, but if you defined them elsewhere, then ok. but are the &amp;quot;?&amp;quot;'s used as part of your echo statement, or not? as that will affect it. also, you can actually make your entire statment in PHP, w/o having to type &amp;lt;?php ...?&amp;gt; for each part of it.



[code]&lt;?php



&lt;html&gt;
&lt;head&gt;
&lt;title&gt;Example&lt;/title&gt;
&lt;/head&gt;
&lt;body&gt;
&lt;p align=&quot;center&quot;&gt;
echo 'Date: &quot;.$todayis.&quot;/n';


echo 'Thank You : &quot;.$visitor.&quot;( &quot;.$visitormail.&quot; )/n';



echo 'Attention: &quot;.$attn.&quot;/n';


echo &quot;Message:&quot;;

$notesout = str_replace(&quot;\r&quot;, &quot;&lt;br/&gt;&quot;, $notes);
echo $notesout;


echo $ip ;
&lt;/p&gt;
?>

thanks m8!